15m^2+73m-10=0

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Solution for 15m^2+73m-10=0 equation:



15m^2+73m-10=0
a = 15; b = 73; c = -10;
Δ = b2-4ac
Δ = 732-4·15·(-10)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5929}=77$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-77}{2*15}=\frac{-150}{30} =-5 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+77}{2*15}=\frac{4}{30} =2/15 $

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